1. Calculate the energy associated with one photon of the radian of wave
Duration: 5:15Posted: Jul 21, 2023
Energy of a photon is given by E=hv=(hc)/(lambda) In the present case, lambda=4000Å=4000 xx 10^(-10) m, c=3.0 xx 10^(8)ms^(-1) and h=6.626 xx 10^(-34)Js. Substituting the values, we have E=(6.626 xx 10^(-34) xx 3.0 xx 10^(8))/(4000 xx 10^(-10))=4.97 xx 10^(-19)J Hence the energy of a photon of the given radiation is 4.97 xx 10^(-19)J.
2. The energy per mole of photon of electromagnetic radiation ... - Socratic
Jun 5, 2018 · "m" in one angstrom, so 4000 Å = 4 xx 10^(-7) "m". Each photon has ... The energy per mole of photon of electromagnetic radiation of wavelength ...
About "300 kJ/mol"... How many "kJ" of energy would "2 mols" of photons with wavelength 4000 Å have? Well, there are 10^(-10) "m" in one angstrom, so 4000 Å = 4 xx 10^(-7) "m". Each photon has energy E = hnu = (hc)/lambda where: h = 6.626 xx 10^(-34) "J"cdot"s" is Planck's constant. c = 2.998 xx 10^8 "m/s" is the speed of light. lambda is the wavelength in "m". nu is the frequency in "s"^(-1). Hence, the energy PER PHOTON is simply: E = (6.626 xx 10^(-34) "J"cdotcancel"s" cdot 2.998 xx 10^8 cancel"m"//cancel"s")/(4 xx 10^(-7) cancel"m") = 4.97 xx 10^(-19) "J/photon" But this number is clunky... since we want the MOLAR photon energy, (4.97 xx 10^(-19) cancel"J")/cancel("photon") xx (6.0221413 xx 10^(23) cancel"photons")/("1 mol") xx ("1 kJ")/(1000 cancel"J") = "299.07 kJ/mol" But since you only gave 1 sig fig, I can only report color(blue)("300 kJ/mol").
3. What is the energy , in joule , associated with a photon ... - Doubtnut
Duration: 5:15Posted: Jul 21, 2023
Energy of a photon E="hc"/lambda=(6.6xx10^(-34)xx3xx10^8)/(4xx10^(-7))=4.95xx10^(-19) J
4. Calculate the energy associated with a photon of wavelength 4000∘A
Duration: 5:15Posted: Mar 15, 2021
Calculate the energy associated with a photon of wavelength 4000 overset@ A
5. What is the number of photons of light with a wavelength of 4000 pm that ...
Energy (E) of a photon = hν. Energy (En) of 'n' photons = nhν ⇒n=E0λhc. Where, λ = wavelength of light = 4000 pm = 4000 × 10–12 m c = velocity of light in ...
What is the number of photons of light with a wavelength of 4000 pm that provide 1 J of energy?
6. A photon of radiation of wavelength 4000 Ao has an energy 'E'. The ...
A photon of radiation of wavelength 4000 oA has an energy 'E'. The wavelength of photon of radiation having energy 0.5E will be. A. 8000 oA. B. 2000 oA.
A photon of radiation of wavelength 4000 Ao has an energy ‘E’. The wavelength of photon of radiation having energy 0.5E will be
7. [Solved] The wavelength of photon is 4000 Å, then the energy wi - Testbook
Jul 4, 2023 · Photon energy is the energy that is carried by a single photon. The amount of this energy is inversely proportional to the wavelength. If the ...
CONCEPT: The photon is a type of elementary particle. It is a basic unit of light. Photons are massless, and they always move at the speed of light in v
![[Solved] The wavelength of photon is 4000 Å, then the energy wi - Testbook](https://i0.wp.com/cdn.testbook.com/meta-data/tb-og-images/tb-social.png)
8. 6.3 How is energy related to the wavelength of radiation?
We can think of radiation either as waves or as individual particles called photons. The energy associated with a single photon is given by E = h ν , where ...
METEO 300 Fundamentals of Atmospheric Science
FAQs
What is the energy of a photon for a wavelength of 4000 Armstrong? ›
The energy of photon is 4. 95×10−19J.
What is the frequency of photon having a wavelength equal to 4000 angstrom? ›7.5 x 1014 Hz. Q.
What is the number of photons of light with a wavelength of 4000? ›Hence, the number of photons with a wavelength of 4000 pm and energy of 1 J are 2.012 × 1016 .
What is the energy of a photon of wavelength 400 nm? ›Solution: From the previous problem, the energy of a single 400 nm photon is 3.1 eV. One must therefore reduce the effective work function to 3.1 eV to allow the light to liberate an electron.
How many metals can show photoelectric effect by using photons of wavelength 4000 å? ›- We found that: Li, Na, K and Mg are having lower values than the incident energy value. So, these metals will show photoelectric effect. Therefore, four metals are showing photoelectric effect.
What will be the energy of a photon in eV of wavelength 5000 å? ›The energy of a photon of light with wavelength 5000∘A is approximately 2.5 eV.
What is the wavelength range of visible light approximately from 4000 angstrom to? ›Light waves have wavelengths between about 400 and 700 nanometers (4,000 to 7,000 angstroms).
How many photons of light having a wavelength 4000 å are necessary to provide 1.0 J of energy? ›=2.01×1018.
What is the ratio of energy of photon 2000 and 4000? ›E1E2=40002000⇒ i.e., λ2λ1=2. Q. The ratio of energies of two photons of wavelengths 2000 A∘ and 4000 A∘.
When a photon of wavelength 4000 is used to break the iodine molecule? ›A photon with a wavelength of 4000Ao is used to break the iodine molecule, then the % of energy converted to the K.E. of iodine atoms if bond dissociation energy of I2 molecule is 246. 5 kJ/mol.
What is the light of wavelength 4000 in Young's experiment? ›
In Young's experiment, light of wavelength 4000 Å is used to produce bright fringes of width 0.6 mm, at a distance of 2 meters.
What is the energy of photon having wavelength 4000 angstrom in eV and in J? ›The energy of photon having wavelength 4000A° in eV and joule are 3.10593 eV and 4.9695 × 10⁻¹⁹ Joule respectively.
What is the energy of a photon of wavelength 444 nm? ›The photon's wavelength is 444 nm. The maximum frequency is 7.50 x 1014 Hz. Each photon has an energy of 2.47 eV.
What is the energy of a photon with a wavelength of 450 nm? ›E = hcλ = 6.625 × 10−27 × 3 × 10104.50 × 10−5 = 4.36 × 10−12 ergs.
Which one has a higher energy a photon of violet light with a wavelength 4000 angstrom or a proton of red light with wavelength 7000 angstrom? ›Answer: Photon of violet light with wavelength 4000A° has a higher energy.............
How much is the energy of a photon of wavelength 6000 armstrong? ›If wavelength of photon is 6000 Å, then its energy will be: 0.66 eV.