## 1. Calculate the energy associated with one photon of the radian of wave

Duration: 5:15Posted: Jul 21, 2023

Energy of a photon is given by E=hv=(hc)/(lambda) In the present case, lambda=4000Å=4000 xx 10^(-10) m, c=3.0 xx 10^(8)ms^(-1) and h=6.626 xx 10^(-34)Js. Substituting the values, we have E=(6.626 xx 10^(-34) xx 3.0 xx 10^(8))/(4000 xx 10^(-10))=4.97 xx 10^(-19)J Hence the energy of a photon of the given radiation is 4.97 xx 10^(-19)J.

## 2. The energy per mole of photon of electromagnetic radiation ... - Socratic

Jun 5, 2018 · "m" in one angstrom, so 4000 Å = 4 xx 10^(-7) "m". Each photon has ... The energy per mole of photon of electromagnetic radiation of wavelength ...

About "300 kJ/mol"... How many "kJ" of energy would "2 mols" of photons with wavelength 4000 Å have? Well, there are 10^(-10) "m" in one angstrom, so 4000 Å = 4 xx 10^(-7) "m". Each photon has energy E = hnu = (hc)/lambda where: h = 6.626 xx 10^(-34) "J"cdot"s" is Planck's constant. c = 2.998 xx 10^8 "m/s" is the speed of light. lambda is the wavelength in "m". nu is the frequency in "s"^(-1). Hence, the energy PER PHOTON is simply: E = (6.626 xx 10^(-34) "J"cdotcancel"s" cdot 2.998 xx 10^8 cancel"m"//cancel"s")/(4 xx 10^(-7) cancel"m") = 4.97 xx 10^(-19) "J/photon" But this number is clunky... since we want the MOLAR photon energy, (4.97 xx 10^(-19) cancel"J")/cancel("photon") xx (6.0221413 xx 10^(23) cancel"photons")/("1 mol") xx ("1 kJ")/(1000 cancel"J") = "299.07 kJ/mol" But since you only gave 1 sig fig, I can only report color(blue)("300 kJ/mol").

## 3. What is the energy , in joule , associated with a photon ... - Doubtnut

Duration: 5:15Posted: Jul 21, 2023

Energy of a photon E="hc"/lambda=(6.6xx10^(-34)xx3xx10^8)/(4xx10^(-7))=4.95xx10^(-19) J

## 4. Calculate the energy associated with a photon of wavelength 4000∘A

Duration: 5:15Posted: Mar 15, 2021

Calculate the energy associated with a photon of wavelength 4000 overset@ A

## 5. What is the number of photons of light with a wavelength of 4000 pm that ...

Energy (E) of a photon = hν. Energy (En) of 'n' photons = nhν ⇒n=E0λhc. Where, λ = wavelength of light = 4000 pm = 4000 × 10–12 m c = velocity of light in ...

What is the number of photons of light with a wavelength of 4000 pm that provide 1 J of energy?

## 6. A photon of radiation of wavelength 4000 Ao has an energy 'E'. The ...

A photon of radiation of wavelength 4000 oA has an energy 'E'. The wavelength of photon of radiation having energy 0.5E will be. A. 8000 oA. B. 2000 oA.

A photon of radiation of wavelength 4000 Ao has an energy ‘E’. The wavelength of photon of radiation having energy 0.5E will be

## 7. [Solved] The wavelength of photon is 4000 Å, then the energy wi - Testbook

Jul 4, 2023 · Photon energy is the energy that is carried by a single photon. The amount of this energy is inversely proportional to the wavelength. If the ...

CONCEPT: The photon is a type of elementary particle. It is a basic unit of light. Photons are massless, and they always move at the speed of light in v

## 8. 6.3 How is energy related to the wavelength of radiation?

We can think of radiation either as waves or as individual particles called photons. The energy associated with a single photon is given by E = h ν , where ...

METEO 300 Fundamentals of Atmospheric Science

## FAQs

### What is the energy of a photon for a wavelength of 4000 Armstrong? ›

The energy of photon is **4.** **95×10−19J**.

**What is the frequency of photon having a wavelength equal to 4000 angstrom? ›**

**7.5 x 10 ^{14} Hz**. Q.

**What is the number of photons of light with a wavelength of 4000? ›**

Hence, the number of photons with a wavelength of 4000 pm and energy of 1 J are **2.012 × 1016** .

**What is the energy of a photon of wavelength 400 nm? ›**

Solution: From the previous problem, the energy of a single 400 nm photon is **3.1 eV**. One must therefore reduce the effective work function to 3.1 eV to allow the light to liberate an electron.

**How many metals can show photoelectric effect by using photons of wavelength 4000 å? ›**

- We found that: Li, Na, K and Mg are having lower values than the incident energy value. So, these metals will show photoelectric effect. Therefore, **four metals** are showing photoelectric effect.

**What will be the energy of a photon in eV of wavelength 5000 å? ›**

The energy of a photon of light with wavelength 5000∘A is approximately **2.5 eV**.

**What is the wavelength range of visible light approximately from 4000 angstrom to? ›**

Light waves have wavelengths between about **400 and 700 nanometers** (4,000 to 7,000 angstroms).

**How many photons of light having a wavelength 4000 å are necessary to provide 1.0 J of energy? ›**

=**2.01×1018**.

**What is the ratio of energy of photon 2000 and 4000? ›**

E1E2=40002000⇒ i.e., λ2λ1=**2**. **Q**. The ratio of energies of two photons of wavelengths 2000 A∘ and 4000 A∘.

**When a photon of wavelength 4000 is used to break the iodine molecule? ›**

A photon with a wavelength of 4000Ao is used to break the iodine molecule, then **the % of energy converted to the K.E. of iodine atoms if bond dissociation energy of I2 molecule is 246.** **5 kJ/mol**.

### What is the light of wavelength 4000 in Young's experiment? ›

In Young's experiment, light of wavelength 4000 Å is **used to produce bright fringes of width 0.6 mm, at a distance of 2 meters**.

**What is the energy of photon having wavelength 4000 angstrom in eV and in J? ›**

The energy of photon having wavelength 4000A° in eV and joule are **3.10593 eV and 4.9695 × 10⁻¹⁹ Joule** respectively.

**What is the energy of a photon of wavelength 444 nm? ›**

The photon's wavelength is 444 nm. The maximum frequency is 7.50 x 1014 Hz. Each photon has an energy of **2.47 eV**.

**What is the energy of a photon with a wavelength of 450 nm? ›**

E = hcλ = 6.625 × 10−27 × 3 × 10104.50 × 10−5 = **4.36 × 10−12 ergs**.

**Which one has a higher energy a photon of violet light with a wavelength 4000 angstrom or a proton of red light with wavelength 7000 angstrom? ›**

Answer: **Photon of violet light with wavelength 4000A°** has a higher energy.............

**How much is the energy of a photon of wavelength 6000 armstrong? ›**

If wavelength of photon is 6000 Å, then its energy will be: **0.66 eV**.